一道貪心模擬,稍微有點意思。不是特別難想到
首先存下X=1 時候的最遠距離,及2*dis+value。記錄此時的邊界pos
接着拿取花費最大的點,並判斷在pos左邊還是右邊,左邊的話+value,右邊的話還需要加上路之間的差
代碼:
#pragma GCC optimize(2)
#include<stdio.h>
#include<algorithm>
#include<string.h>
#include<string>
#include<math.h>
#include<set>
#include<vector>
#include<iostream>
#include<queue>
#include<map>
#include<math.h>
#include<stack>
#include<bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 100;
const int inf = 0x3f3f3f3f;
typedef long long ll;
struct node
{
int u, v, pos;
bool flag;
}edge[maxn];
bool cmp(node a, node b)
{
return a.v > b.v;
}
map<long long, long long>mp;
int main()
{
//freopen("C://input.txt", "r", stdin);
int n;
cin >> n;
int _max = -1;
int _u= -1;
int _pos = -1;
for (int i = 1; i <= n; i++)
{
cin >> edge[i].u;
}
for (int i = 1; i <= n; i++)
{
cin >> edge[i].v;
edge[i].pos = i;
edge[i].flag = true;//未走過
if (edge[i].u * 2 + edge[i].v > _max)
{
_max = edge[i].u * 2 + edge[i].v;
_u= edge[i].u;
_pos = edge[i].pos;
}
}
edge[_pos].flag = false;
sort(edge + 1, edge + n + 1, cmp);
ll sum = 0;
sum += _max;
for (int i = 1; i <= n; i++)
{
if (!mp[sum])
{
cout << sum << endl;
mp[sum] = 1;
}
if (edge[i].u >= _u&&edge[i].flag)
{
edge[i].flag = false;
sum += abs(_u - edge[i].u) * 2 + edge[i].v;
_u = edge[i].u;
}
else if (edge[i].flag)
{
edge[i].flag = false;
sum += edge[i].v;
}
}
if (!mp[sum])
{
cout << sum << endl;
mp[sum] = 1;
}
return 0;
}
#pragma GCC optimize(2)
#include<stdio.h>
#include<algorithm>
#include<string.h>
#include<string>
#include<math.h>
#include<set>
#include<vector>
#include<iostream>
#include<queue>
#include<map>
#include<math.h>
#include<stack>
#include<bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 100;
const int inf = 0x3f3f3f3f;
typedef long long ll;
struct node
{
int u, v, pos;
bool flag;
}edge[maxn];
bool cmp(node a, node b)
{
return a.v > b.v;
}
map<long long, long long>mp;
int main()
{
//freopen("C://input.txt", "r", stdin);
int n;
cin >> n;
int _max = -1;
int _u= -1;
int _pos = -1;
for (int i = 1; i <= n; i++)
{
cin >> edge[i].u;
}
for (int i = 1; i <= n; i++)
{
cin >> edge[i].v;
edge[i].pos = i;
edge[i].flag = true;//未走過
if (edge[i].u * 2 + edge[i].v > _max)
{
_max = edge[i].u * 2 + edge[i].v;
_u= edge[i].u;
_pos = edge[i].pos;
}
}
edge[_pos].flag = false;
sort(edge + 1, edge + n + 1, cmp);
ll sum = 0;
sum += _max;
for (int i = 1; i <= n; i++)
{
if (!mp[sum])
{
cout << sum << endl;
mp[sum] = 1;
}
if (edge[i].u >= _u&&edge[i].flag)
{
edge[i].flag = false;
sum += abs(_u - edge[i].u) * 2 + edge[i].v;
_u = edge[i].u;
}
else if (edge[i].flag)
{
edge[i].flag = false;
sum += edge[i].v;
}
}
if (!mp[sum])
{
cout << sum << endl;
mp[sum] = 1;
}
return 0;
}