txt矩陣

最近在寫一個程序， 要求如下：
1.txt文件中有一個m*n的數字矩陣，
2.txt文件中也有一個m*n的數字矩陣，
編寫程序， 創建3.txt文件， 使得其中存儲一個m*n的矩陣， 矩陣的元素爲對應的1.txt與2.txt中元素的和。

目前， 寫了一段程序， 只能實現1*1的矩陣相加， 正在努力完善程序。 程序如下：

#include<stdio.h>
#include<string.h>
#include<math.h>

int count = 0;
long ft1 = 1L;
long ft2 = 1L;
int turn1 = 1;
int turn2 = 1;

int main()
{
    FILE *matrix1 = fopen("matrix1.txt", "r");
    if (NULL == matrix1)
    {
        perror("open1");
        return 1;
    }

    FILE *matrix2 = fopen("matrix2.txt", "r");
    if (NULL == matrix2)
    {
        perror("open2");
        fclose(matrix1);
        return 2;
    }

    FILE *sum = fopen("sum.txt", "a");
    if (NULL == sum)
    {
        perror("open3");
        fclose(matrix1);
        fclose(matrix2);
        return 3;
    }

    char butter1[10] = {0};
    char butter2[10] = {0};
    char butter3[10] = {0};
    char vote1[1] = {0};
    char vote2[1] = {0};

    fseek(matrix1, ft1, SEEK_SET);
    int end1 = feof(matrix1);
    fseek(matrix2, ft2, SEEK_SET);
    int end2 = feof(matrix2);
//    while (0 == end1 && 0 == end2)
//{

    printf("turn = %d %d\n", turn1, turn2);
    printf("ft1 = %ld\n", ft1);
    printf("ft2 = %ld\n", ft2);
int length1 = lenth1(matrix1);
int length2 = lenth2(matrix2);
//    printf("lenth = %d %d\n", lenth1(matrix1), lenth2(matrix2));
    fread(butter1, sizeof(char), length1, matrix1);
    fread(butter2, sizeof(char), length2, matrix2);
    add(length1, butter1, length2, butter2, butter3);
//    fread(butter1, sizeof(char), lenth1(matrix1), matrix1);
//    fread(butter2, sizeof(char), lenth2(matrix2), matrix2);
//    add(lenth1(matrix1), butter1, lenth2(matrix2), butter2, butter3);
    fwrite(butter3, sizeof(char), count, sum);
    fwrite(" ", sizeof(char), 1, sum);
    memset(butter1, 0, 10);
    memset(butter2, 0, 10);
    memset(butter3, 0, 10);
    printf("\n");
//}
    return 0;
}

int lenth1(FILE *file)
{
    int nmeb = 0;
    char judge[1] = {'0'};
    char judge2[1] = {'0'};

//    fseek(file, 0, SEEK_SET);
    int Boolean;
    if (turn1 <= 1)
    {
    Boolean = fseek(file, 0, SEEK_SET);
    }
    else
    {
    Boolean = fseek(file, ft1, SEEK_SET);
//printf("boo = %d\n", Boolean);
    }
    if (0 == Boolean)
    {
        fread(judge, sizeof(char), 1, file);
        if (' ' == judge[0])
        {
            fseek(file, 1, SEEK_CUR);
            memset(judge, 0, 1);
            fread(judge2, sizeof(char), 1, file);
        }

        while (' ' != judge2[0])
        {
            nmeb++;
            memset(judge2, 0, 1);
            fread(judge2, sizeof(char), 1, file);
        }
    }

    ft1 = ftell(file);
    turn1++;

    fseek(file, 0, SEEK_SET);
    return(nmeb);
}
int lenth2(FILE *file)
{
    int nmeb = 0;
    char judge[1] = {'0'};
    char judge2[1] = {'0'};
//    fseek(file, 0, SEEK_SET);
    int Boolean;
    if (turn2 <= 1)
    {
    Boolean = fseek(file, 0, SEEK_SET);
    }
    else
    {
    Boolean = fseek(file, ft2, SEEK_SET);
    }

    if (0 == Boolean)
    {
        fread(judge, sizeof(char), 1, file);
        if (' ' == judge[0])
        {
            fseek(file, 1, SEEK_CUR);
            memset(judge, 0, 1);
            fread(judge2, sizeof(char), 1, file);
        }

        while (' ' != judge2[0])
        {
            nmeb++;
            memset(judge2, 0, 1);
            fread(judge2, sizeof(char), 1, file);
        }
    }

    ft2 = ftell(file);
    turn2++;

    fseek(file, 0, SEEK_SET);
    return(nmeb);
}

int add(int len1, char* pb1, int len2, char* pb2, char* pb3)
{
    int a, b, c;
    a = int_change(len1, pb1);
    b = int_change(len2, pb2);
    printf("%d %d\n", a, b);
    c = a + b;
    printf("%d\n", c);

    char_change(c, pb3);
}

int int_change(int len, char* pb)
{
    int tmp = len;
    int i;
    int rv = 0;
    for (tmp = len - 1, i = 0; tmp >= 0; tmp--, i++)
    {
        rv = rv + (pb[i]-'0') * pow(10, tmp);
    }
    return(rv);
}

int char_change(int c, char* pb3)
{
    int tmp = c;
    int len = 1;
    while (0 != tmp / 10)
    {
        len++;
        tmp = tmp / 10;
    }

    count = len;

    int tmp2 = c;
    while (len > 0)
    {
        pb3[len - 1] = (tmp2 % 10) + '0';
        len--;
        tmp2 = tmp2 / 10;
    }
//printf("pb3: %s", pb3);
}