Question
Given an array nums, write a function to move all 0’s to the end of it while maintaining the relative order of the non-zero elements.
For example, given nums = [0, 1, 0, 3, 12], after calling your function, nums should be [1, 3, 12, 0, 0].
Note
- You must do this in-place without making a copy of the array.
- Minimize the total number of operations.
Java Code
public void moveZeroes(int[] nums) {
int len = nums.length;
int i = 0;
//遍歷數組前面連續的非零元素
while(nums[i] != 0)
if((++i) == len) return;
//指針j用於依次遍歷數組的元素,指針i指向需要被覆蓋的元素
//即把所有非零元素全部移動到數組前部,且按照原來的順序緊挨在一起
int j = i;
while(j < len) {
if(nums[j] != 0)
nums[i++] = nums[j];
++j;
}
//先得到數組中0的個數,再把數組後部置零,相當於把所有0後移
int zeros = j - i;
while(zeros > 0) {
nums[len - zeros] = 0;
--zeros;
}
}