codeforces 456A

需要找到性價比最高的電腦（它的價格比某臺電腦低，但質量更好），因此我首先寫了雙重循環（小函數調用），結果

顯示Time limit exceeded on test 6

def lalala(price,quality,start_index,n):
    for i in range(start_index,n):
        if price[start_index] < price[i] and quality[start_index] > quality[i]:
            return True
    return False


n = int(raw_input())
price = []
quality=[]
for i in range(n):
    line = map(int,raw_input().split())
    price.append(line[0])
    quality.append(line[1])

result = False
for i in range(n):
    result = lalala(price,quality,i,n)
    if result == True:
        break

if result == True:
    print "Happy Alex"
else:
    print "Poor Alex"

因此，只能想別的思路。先去寫，通過了再上傳