Leetcode:Remove Element

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn’t matter what you leave beyond the new length.

public int removeElement(int[] A, int elem) {

    }

給你一個數組，和一個值，移除所有該值的元素，返回新長度。

數組元素順序可變，只要返回正確的新長度即可。

    public int removeElement(int[] A, int elem) {
        if(A.length==0) return 0;
        int p=0;
        for(int i=0;i<A.length;i++){
            if(A[i]!=elem){
                A[p++]=A[i];
            }
        }
        return p;
    }