微軟2014實習生及秋令營技術類職位在線測試——String reorder

題目 : String reorder

時間限制:10000ms

單點時限:1000ms

內存限制:256MB

Description

For this question, your program is required to process an input string containing only ASCII characters between ‘0’ and ‘9’, or between ‘a’ and ‘z’ (including ‘0’, ‘9’, ‘a’, ‘z’).

Your program should reorder and split all input string characters into multiple segments, and output all segments as one concatenated string. The following requirements should also be met,
1. Characters in each segment should be in strictly increasing order. For ordering, ‘9’ is larger than ‘0’, ‘a’ is larger than ‘9’, and ‘z’ is larger than ‘a’ (basically following ASCII character order).
2. Characters in the second segment must be the same as or a subset of the first segment; and every following segment must be the same as or a subset of its previous segment.

Your program should output string “<invalid input string>” when the input contains any invalid characters (i.e., outside the '0'-'9' and 'a'-'z' range).

Input

Input consists of multiple cases, one case per line. Each case is one string consisting of ASCII characters.

Output

For each case, print exactly one line with the reordered string based on the criteria above.

樣例輸入

aabbccdd
007799aabbccddeeff113355zz
1234.89898
abcdefabcdefabcdefaaaaaaaaaaaaaabbbbbbbddddddee

樣例輸出

abcdabcd
013579abcdefz013579abcdefz
<invalid input string>
abcdefabcdefabcdefabdeabdeabdabdabdabdabaaaaaaa

#include <iostream>
#include <string>

using namespace std;

int main(void) {
	string str[1024];
	int num[36],i=0,j=0,m=0,n=0;
	bool flag;
	getline(cin,str[n]);
	while(!str[n].empty())
	{
		n++;
		getline(cin,str[n]);
	}
	while(m<n)
	{
		for(i=0;i<36;i++)
			num[i]=0;
		i=0;
		flag=true;
		while(i<str[m].length())
		{
			if(str[m][i]>='0'&&str[m][i]<='9')
			{
				num[str[m][i]-48] += 1;
			}
			else if(str[m][i]>='a'&&str[m][i]<='z')
			{
				num[str[m][i]-87] += 1;
			}
			else
			{
				flag=false;
				cout<<"<invalid input string>"<<endl;
				break;
			}
			i++;
		}
		if(flag)
		{
			while(i--)
			{
				for(j=0;j<36;j++)
				{
					if(j>=0&&j<=9)
					{
						if(num[j]>0)
						{
							cout<<char(j+48);
							num[j]--;
						}
					}
					else
					{
						if(num[j]>0)
						{
							cout<<char(j+87);
							num[j]--;
						}
					}
				}
			}
			cout<<endl;
		}
		m++;
	}
	system("PAUSE");
    return 0;
}