題目:Fizz Buzz
題目詳情:
Write a program that outputs the string representation of numbers from 1 to n.
But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.
翻譯:
輸入一個整數,返回一個由1到n組成的有序的數組,但是在3的倍數的位置輸出”Fizz”,在5的倍數的位置輸出”Buzz”,在同時是3和5的倍數的位置輸出”FizzBuzz”.
輸出樣例:
n = 15,
Return:
[
“1”,
“2”,
“Fizz”,
“4”,
“Buzz”,
“Fizz”,
“7”,
“8”,
“Fizz”,
“Buzz”,
“11”,
“Fizz”,
“13”,
“14”,
“FizzBuzz”
]
答案:
public class Solution {
public List<String> fizzBuzz(int n) {
String[] insteads = {"Fizz", "Buzz", "FizzBuzz"};
List<String> rst = new LinkedList<>();
for (int i=1; i<=n; i++) {
if (i%3==0 && i%5==0)
rst.add(insteads[2]);
else if (i%3==0)
rst.add(insteads[0]);
else if (i%5==0)
rst.add(insteads[1]);
else
rst.add(i+"");
}
return rst;
}
}