Given a binary tree, return the bottom-up level order traversal of its nodes’ values. (ie, from left to right, level by level from leaf to root).
For example:
Given binary tree [3,9,20,null,null,15,7],
3 / \ 9 20 / \ 15 7
return its bottom-up level order traversal as:
[ [15,7], [9,20], [3] ]
思路:和之前Binary Tree Level Order Traversal這個一樣,只不過最後reverse反轉一下,倒序。
方法一:遞歸。
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> levelOrderBottom(TreeNode* root) {
vector<vector<int>>result;
traverse(root,result,1);
reverse(result.begin(),result.end());
return result;
}
void traverse(TreeNode* root,vector<vector<int>>&result,int level){
if(!root) return;
if(level>result.size()){
result.push_back(vector<int>());
}
result[level-1].push_back(root->val);
traverse(root->left,result,level+1);
traverse(root->right,result,level+1);
}
};