瘋狂元寶的代碼分析 揭露噁心的騰訊

瘋狂元寶的代碼分析

騰訊推出了一個老虎機的遊戲，名字叫瘋狂元寶，女友比較喜歡玩，所以拼命掙銀幣來給她玩，可是玩了好久直到每天限制的100次最大隻中了一個5倍，把她鬱悶壞了，我覺的按概率不應該這樣，就把他的flash反編譯了，真是不看不知道，一看下一跳，騰訊真噁心。只能用噁心形容了。

 

這個picstop函數應該是老虎機停止的函數。

下面來對他的這個函數進行一下分析，使用了swith，即停止的情況一共有-4~~8這13種情況。

他構建了三個初始化數組

                ran1 = [2, 4, 6, 8, 10, 12];

                ran2 = [2, 4, 6, 8, 10, 12];

                ran3 = [2, 4, 6, 8, 10, 12];

這裏面2是代表諾基亞

-4~~0這五種情況的可選數組裏都沒有2，並且都是用while語句使其不能產生三個相同的，即這五種情況任何獎都不可能中。

1爲全2

2爲全4

3爲全6

4爲全8

5爲全10

6爲全12

7 可供選擇的數組裏沒2，他產生一個隨機數0-3，

這個隨機數如果爲0則1，2洞爲2，爲1則1，3洞爲2，否則的話2，3洞爲2，總之就是這種情況爲中2個2即中5倍。

       8 可選數組中有2，但他使用了1個嵌套while循環，使結果只產生一個2

       而他的這個prize值是通過服務端的某一算法生成的，即生成之後再傳遞到客戶端來，你每次中沒中，中什麼開獎之前服務端就已經知道了。

可見中獎的結果是騰訊來控制的，如果他發發慈心後臺算法上prize可能返回1，那估計我們還有希望中大獎，否則只有累死你的小手和大腦了。

他的這個while語句真夠噁心的。

while (((_local1 == _local3) and (_local3 == _local2)) and (_local1 == _local2)) {

                    _local1 = ran1[random (5)];

                    _local3 = ran2[random (5)];

                    _local2 = ran3[random (5)];

                }

 

   function picstop() {

        switch (_root.prize) {

            case -4 :

                var ran1;

                var ran2;

                var ran3;

                var _local1;

                var _local3;

                var _local2;

                ran1 = [4, 6, 8, 10, 12];

                ran2 = [4, 6, 8, 10, 12];

                ran3 = [4, 6, 8, 10, 12];

                _local1 = ran1[random (5)];

                _local3 = ran2[random (5)];

                _local2 = ran3[random (5)];

                while (((_local1 == _local3) and (_local3 == _local2)) and (_local1 == _local2)) {

                    _local1 = ran1[random (5)];

                    _local3 = ran2[random (5)];

                    _local2 = ran3[random (5)];

                }

                _root.dong1 = _local1;

                _root.dong2 = _local3;

                _root.dong3 = _local2;

                return;

            case -3 :

                var ran1;

                var ran2;

                var ran3;

                ran1 = [4, 6, 8, 10, 12];

                ran2 = [4, 6, 8, 10, 12];

                ran3 = [4, 6, 8, 10, 12];

                var _local1 = ran1[random (5)];

                var _local3 = ran2[random (5)];

                var _local2 = ran3[random (5)];

                while (((_local1 == _local3) and (_local3 == _local2)) and (_local1 == _local2)) {

                    _local1 = ran1[random (5)];

                    _local3 = ran2[random (5)];

                    _local2 = ran3[random (5)];

                }

                _root.dong1 = _local1;

                _root.dong2 = _local3;

                _root.dong3 = _local2;

                return;

            case -2 :

                var ran1;

                var ran2;

                var ran3;

                ran1 = [4, 6, 8, 10, 12];

                ran2 = [4, 6, 8, 10, 12];

                ran3 = [4, 6, 8, 10, 12];

                var _local1 = ran1[random (5)];

                var _local3 = ran2[random (5)];

                var _local2 = ran3[random (5)];

                while (((_local1 == _local3) and (_local3 == _local2)) and (_local1 == _local2)) {

                    _local1 = ran1[random (5)];

                    _local3 = ran2[random (5)];

                    _local2 = ran3[random (5)];

                }

                _root.dong1 = _local1;

                _root.dong2 = _local3;

                _root.dong3 = _local2;

                return;

            case -1 :

                var ran1;

                var ran2;

                var ran3;

                ran1 = [4, 6, 8, 10, 12];

                ran2 = [4, 6, 8, 10, 12];

                ran3 = [4, 6, 8, 10, 12];

                var _local1 = ran1[random (5)];

                var _local3 = ran2[random (5)];

                var _local2 = ran3[random (5)];

                while (((_local1 == _local3) and (_local3 == _local2)) and (_local1 == _local2)) {

                    _local1 = ran1[random (5)];

                    _local3 = ran2[random (5)];

                    _local2 = ran3[random (5)];

                }

                _root.dong1 = _local1;

                _root.dong2 = _local3;

                _root.dong3 = _local2;

                return;

            case "0" :

                var ran1;

                var ran2;

                var ran3;

                ran1 = [4, 6, 8, 10, 12];

                ran2 = [4, 6, 8, 10, 12];

                ran3 = [4, 6, 8, 10, 12];

                var _local1 = ran1[random (5)];

                var _local3 = ran2[random (5)];

                var _local2 = ran3[random (5)];

                while (((_local1 == _local3) and (_local3 == _local2)) and (_local1 == _local2)) {

                    _local1 = ran1[random (5)];

                    _local3 = ran2[random (5)];

                    _local2 = ran3[random (5)];

                }

                _root.dong1 = _local1;

                _root.dong2 = _local3;

                _root.dong3 = _local2;

                return;

            case "1" :

                _root.dong1 = 2;

                _root.dong2 = 2;

                _root.dong3 = 2;

                return;

            case "2" :

                _root.dong1 = 4;

                _root.dong2 = 4;

                _root.dong3 = 4;

                return;

            case "3" :

                _root.dong1 = 6;

                _root.dong2 = 6;

                _root.dong3 = 6;

                return;

            case "4" :

                _root.dong1 = 8;

                _root.dong2 = 8;

                _root.dong3 = 8;

                return;

            case "5" :

                _root.dong1 = 10;

                _root.dong2 = 10;

                _root.dong3 = 10;

                return;

            case "6" :

                _root.dong1 = 12;

                _root.dong2 = 12;

                _root.dong3 = 12;

                return;

            case "7" :

                var ranx;

                var ranran;

                ranran = random (3);

                ranx = [4, 6, 8, 10, 12];

                if (ranran == 0) {

                    var _local1 = 2;

                    var _local3 = 2;

                    var _local2 = ranx[random (5)];

                } else if ((ranran = 1)) {

                    var _local1 = 2;

                    var _local3 = ranx[random (5)];

                    var _local2 = 2;

                } else {

                    var _local1 = ranx[random (5)];

                    var _local3 = 2;

                    var _local2 = 2;

                 }

                _root.dong1 = _local1;

                _root.dong2 = _local3;

                _root.dong3 = _local2;

                return;

            case "8" :

                var ran1;

                var ran2;

                var ran3;

                ran1 = [2, 4, 6, 8, 10, 12];

                ran2 = [2, 4, 6, 8, 10, 12];

                ran3 = [2, 4, 6, 8, 10, 12];

                do {

                    var _local1 = ran1[random (6)];

                    var _local3 = ran2[random (6)];

                    var _local2 = ran3[random (6)];

                    while (((_local1 != 2) and (_local3 != 2)) and (_local2 != 2)) {

                       _local1 = ran1[random (6)];

                        _local3 = ran2[random (6)];

                        _local2 = ran3[random (6)];

                    }

                } while (((((_local1 == 2) and (_local3 == 2)) or ((_local1 == 2) and (_local2 == 2))) or ((_local3 == 2) and (_local2 == 2))) or (((_local1 == 2) and (_local3 == 2)) and (_local2 == 2)));

                _root.dong1 = _local1;

                _root.dong2 = _local3;

                _root.dong3 = _local2;

                return;

        }

}

 

我們再來看騰訊的廣告詞：

想讓你的元寶數量暴漲嗎？快來參加“瘋狂元寶”遊戲吧。。。

相信看了代碼的分析，聰明的網民應該很清楚，所謂的瘋狂元寶不僅不會使您的元寶暴漲，反而會讓您的元寶迅速被遊戲吸收殆盡。