Description
We are playing the Guess Game. The game is as follows:
I pick a number from 1 to n. You have to guess which number I picked.
Every time you guess wrong, I’ll tell you whether the number is higher or lower.
You call a pre-defined API guess(int num)
which returns 3 possible results (-1
, 1
, or 0
):
-1 : My number is lower 1 : My number is higher 0 : Congrats! You got it!
Example:
n = 10, I pick 6. Return 6.
Analysis
二分搜索。要注意使用
//Assume [a,b]
(b - a) / 2 + a
而不是
(a + b) / 2
以防止溢出。
Code
// Forward declaration of guess API.
// @param num, your guess
// @return -1 if my number is lower, 1 if my number is higher, otherwise return 0
int guess(int num);
class Solution {
public:
int guessNumber(int n) {
return search(1,n);
}
private:
int search(int a, int b){
int m = (b - a) / 2 + a;
int g = guess (m);
if (g == 0) return m;
else if (g == 1) return search (m + 1, b);
else if (g == -1) return search (a, m -1);
}
};
Appendix
- Link: https://leetcode.com/problems/guess-number-higher-or-lower/
- Run Time: 0ms