Compare two version numbers version1 and version1.
If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the .
character.
The .
character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5
is not "two and a half" or "half way to version three", it is the fifth
second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
class Solution {
public:
int compareVersion(string version1, string version2) {
int i = 0,j=0;
int num1,num2;
while(i<version1.size()||j<version2.size())
{
num1 = 0,num2 = 0;
while(version1[i]!='.'&&i<version1.size())
{
num1 = num1*10 + version1[i]-'0';
i++;
}
while(version2[j]!='.'&&j<version2.size())
{
num2 = num2*10 + version2[j]-'0';
j++;
}
if(num1 > num2) return 1;
if(num1 < num2) return -1;
i++;
j++;
}
return 0;
}
};