Reverse digits of an integer.
Example1: x = 123, return 321
Example2: x = -123, return -321
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第一反應把代碼寫成:
package leetcode;
public class Solution {
public static int reverse(int x) {
String s = Integer.toString(x);
int len = s.length();
String str="";
if (x < 0) {// 說明含有負號
str="-";
for (int i = len-1; i>=1; i--) {
str=str+s.charAt(i);
}
} else {
for (int i = len-1; i>=0; i--) {
str=str+s.charAt(i);
}
}
int result=Integer.valueOf(str);
return result;
}
public static void main(String[] args) {
System.out.println(reverse(1534236469));
}
}
結果出現:
正好是十位數的時候的問題,代碼中用到的Integer.valueOf是強制轉換string到int,但是十位好過了int的數據範圍,所以報錯了。
package leetcode;
public class Solution {
public static int reverse(int x) {
long result = 0;
while (x != 0) {
result = (result * 10) + (x % 10);
if (result > Integer.MAX_VALUE || result < Integer.MIN_VALUE) {// 時刻檢查,要求result不可以超出範圍
return 0;
}
x = x / 10;
}
return (int) result;
}
public static void main(String[] args) {
System.out.println(reverse(1534236469));
}
}