題目:
Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array.
Formally the function should:
Return true if there exists i, j, k
such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return false.
Your algorithm should run in O(n) time complexity and O(1) space complexity.
Examples:
Given [1, 2, 3, 4, 5]
,
return true
.
Given [5, 4, 3, 2, 1]
,
return false
.
代碼:
bool increasingTriplet(vector<int>& nums) {
if(nums.size()<3) return false;
int min = nums[0]; //
int maxer = INT_MAX;
for(int i=1;i<nums.size();i++){ //設置三種狀態
if(nums[i]<=min) min=nums[i]; //狀態一:小於最小值,則更新最小值
else if(nums[i]<maxer) maxer=nums[i]; //狀態二:大於最小值,且小於次大值,則更新次大值
else if(nums[i]>maxer) return true; //狀態三:大於次大值,則代表有三個數是遞增關係
}
return false;
}