405. Convert a Number to Hexadecimal

Given an integer, write an algorithm to convert it to hexadecimal. For negative integer, two’s complement method is used.

Note:

  1. All letters in hexadecimal (a-f) must be in lowercase.
  2. The hexadecimal string must not contain extra leading 0s. If the
    number is zero, it is represented by a single zero character ‘0’;
    otherwise, the first character in the hexadecimal string will not be
    the zero character.
  3. The given number is guaranteed to fit within the range of a 32-bit
    signed integer.
  4. You must not use any method provided by the library which
    converts/formats the number to hex directly.
Example 1:

Input:
26

Output:
"1a"
Example 2:

Input:
-1

Output:
"ffffffff"

解法一:Language-Java Run Time-7ms
注意:一個數以二進制形式存放在內存中,負數以它的補碼形式存在

    public String toHex(int num) {
        StringBuffer sb = new StringBuffer();
        if(num == 0)
        {
            sb.append(0);
        }else{
            while(num != 0){
                //取num的後位
                int n = num & 0xf;
                if(n >= 0xa){
                    n = n - 10 + 'a';
                }else{
                    n = n + '0';
                }
                sb.append((char)n);
                //無符號右移,忽略符號位,空位都以0補齊
                num = num >>> 4;
            }
        }
        return sb.reverse().toString();
    }
發表評論
所有評論
還沒有人評論,想成為第一個評論的人麼? 請在上方評論欄輸入並且點擊發布.
相關文章