1、有三張表，用戶表，用戶角色表，角色表，
使用sql顯示如下內容：
用戶ID，用戶名，超級管理員，錄入員，會計
也就是角色用逗號分隔。
解：
1、填充數據到表User
select * from [User]
INSERT INTO [northwind].[dbo].[User]
([ID]
,[NAME])
VALUES
(1
,'zhaohy')
INSERT INTO [northwind].[dbo].[User]
([ID]
,[NAME])
VALUES
(2
,'zhangyy')
GO
2、填充數據到表role
select * from [role]
INSERT INTO [northwind].[dbo].[Role]
([ID]
,[RoleName])
VALUES
(1
,'senior software engineer')
INSERT INTO [northwind].[dbo].[Role]
([ID]
,[RoleName])
VALUES
(2
,'project manager')
INSERT INTO [northwind].[dbo].[Role]
([ID]
,[RoleName])
VALUES
(3
,'UI Disigner')
INSERT INTO [northwind].[dbo].[Role]
([ID]
,[RoleName])
VALUES
(4
,'Tester')
GO
3、填充數據到表Role_User
select * from Role_User
INSERT INTO [northwind].[dbo].[Role_User]
([RoleID]
,[UserID])
VALUES
(1
,1)
GO
INSERT INTO [northwind].[dbo].[Role_User]
([RoleID]
,[UserID])
VALUES
(2
,1)
INSERT INTO [northwind].[dbo].[Role_User]
([RoleID]
,[UserID])
VALUES
(3
,1)
INSERT INTO [northwind].[dbo].[Role_User]
([RoleID]
,[UserID])
VALUES
(4
,2)
4、查詢出來：
drop table #result;
select * into #result from (select u.ID,u.NAME,ru.RoleID,r.RoleName from [user] u inner join Role_User ru on ru.UserID =u.ID inner join [Role] r
on ru.RoleID=r.ID) as t;
select * from #result;
select id,name, [RoleName] = stuff((select ',' + [RoleName] from #result t where id = #result.id for xml path('')) , 1 , 1 , '')
from #result
group by id ,name;
drop table #result;
輸出結果：
