[leetCode] Intersection of Two Linked Lists

Write a program to find the node at which the intersection of two singly linked lists begins.

For example, the following two linked lists: 

A:          a1 → a2
                   ↘
                     c1 → c2 → c3
                   ↗            
B:     b1 → b2 → b3

begin to intersect at node c1.

Notes:

  • If the two linked lists have no intersection at all, return null.
  • The linked lists must retain their original structure after the function returns. 
  • You may assume there are no cycles anywhere in the entire linked structure.
  • Your code should preferably run in O(n) time and use only O(1) memory.

Credits:
Special thanks to @stellari for adding this problem and creating all test cases.

public ListNode getIntersectionNode(ListNode headA, ListNode headB) {
        if (headA == null || headB == null) return null;
        int len1 = 0, len2 = 0;
        ListNode tmpA = headA;

        while(tmpA != null) {
            len1++;
            tmpA = tmpA.next;
        }
        tmpA = headA;
        ListNode tmpB = headB;
        while(tmpB != null) {
            len2++;
            tmpB = tmpB.next;
        }
        tmpB = headB;
        if (len1 > len2) {
            for (int i = 0; i < len1 - len2; i++) {
                tmpA = tmpA.next;
            }
        }
        else if (len1 < len2) {
            for (int i = 0; i < len2 - len1; i++) {
                tmpB = tmpB.next;
            }
        }
        while(tmpA!= null) {
            if (tmpA.equals(tmpB)) return tmpA;
            tmpA = tmpA.next;
            tmpB = tmpB.next;
        }
        return tmpA;
    }


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