[leetCode] Maximum Gap

Given an unsorted array, find the maximum difference between the successive elements in its sorted form.

Try to solve it in linear time/space.

Return 0 if the array contains less than 2 elements.

You may assume all elements in the array are non-negative integers and fit in the 32-bit signed integer range.

Credits:
Special thanks to @porker2008 for adding this problem and creating all test cases.

public class Solution {
    public int maximumGap(int[] num) {
        if (num.length < 2) return 0;
        int min = num[0], max = num[0];

        for (int i : num) {
            min = Math.min(min, i);
            max = Math.max(max, i);
        }

        int len = (max - min)/num.length + 1;
        boolean[] flag = new boolean[(max - min)/len + 1];
        int[][] bucket = new int[(max-min)/len + 1][2];

        for (int x : num) {
            int i = (x-min)/len;
            if (flag[i] == false) {
                flag[i] = true;
                bucket[i][0] = x;
                bucket[i][1] = x;
            } else {
                bucket[i][0] = Math.min(bucket[i][0], x);
                bucket[i][1] = Math.max(bucket[i][1], x);
            }
        }
        int gap = bucket[0][1] - bucket[0][0];
        int prev = 0;

        for( int i = 1; i < flag.length; i++) {
            if (flag[i] == false) continue;
            gap = Math.max(gap, bucket[i][0] - bucket[prev][1]);
            prev = i;
        }

        return gap;
    }
}



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