153. Find Minimum in Rotated Sorted Array
Medium
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Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., [0,1,2,4,5,6,7]
might become [4,5,6,7,0,1,2]
).
Find the minimum element.
You may assume no duplicate exists in the array.
Example 1:
Input: [3,4,5,1,2] Output: 1
Example 2:
Input: [4,5,6,7,0,1,2] Output: 0
這道題沒什麼太多彎路,就二分法縷清楚就行,Accepted代碼如下:
class Solution {
public int findMin(int[] nums) {
int l = nums.length;
if (l == 1) {
return nums[0];
}
int start = 0;
int end = l - 1;
while (start < end - 1) {
int mid = (start + end) / 2;
if (nums[mid] < nums[end]) {
end = mid;
} else {
start = mid;
}
}
return Math.min(nums[start], nums[end]);
}
}
這解法顯示超過100%的時間複雜度和87.5%的空間複雜度,看來還算優的