Problem Description
Your task is to calculate the sum of some integers.
Input
Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.
Output
For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.
Sample Input
3
4 1 2 3 4
5 1 2 3 4 5
3 1 2 3
Sample Output
10
15
6
我的代碼如下：
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <errno.h>
int main(int argc,char **argv){
int row; //將要輸入的行
int rowmax;//每行輸入整數個數
scanf("%d",&row);
int *pt[row];
int result[row];
memset(result,0,sizeof(int) * row);
int i=row;
for(;row>0;row--){
scanf("%d",&rowmax);
pt[row-1]=(int *)malloc(rowmax * sizeof(int));
if(pt[row-1]==NULL){
perror(strerror(errno));
}
else{
for(;rowmax>0;rowmax--){
scanf("%d",pt[row-1]);
result[row-1]+=*pt[row-1];
pt[row-1]++;
}
}
}
for(;i>0;i--)
printf("%d\n\n",result[i-1]);
return 0;
}
注：我動態申請的空間用完後沒有釋放，因不知指針數組空間如何釋放。
下面代碼是別人所寫，拿來對比：
#include <stdio.h>#include <stdlib.h>#include <ctype.h>#include <string.h>int main (int argc,char*argv[]){ int row; int i,j=0; char num; int* result=NULL; printf("Enter the row: "); scanf("%d",&row); result = malloc(row*sizeof(int)); memset(result,0,sizeof(result)); getchar(); for (i=0;i<row;i++) { result[i] = 0; num = getchar(); while(1) { num = getchar(); if (num == '\n') { break; } else if (num != ' ') { result[i]+=(num-0x30); } } } for (i=0;i<row;i++) { printf("%d\n\n",result[i]); } return 0;}