http://acm.hdu.edu.cn/showproblem.php?pid=1108
最小公倍數
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 32700 Accepted Submission(s): 18237
對於 最小公倍數乘以最大公約數 = A*B。
<strong><span style="font-family:KaiTi_GB2312;font-size:18px;"><span style="font-size:24px;">#include<iostream>
#include<cmath>
using namespace std;
int main()
{
long int a,b,m;
int i;
while(~scanf("%ld%ld",&a,&b))
{
if(a>b)
m=a;
else
m=b;
for(i=m;i<a*b;i+=m)//i+=m
{
if(i%a==0&&i%b==0)
{
break;
}
}
printf("%d\n",i);
}
return 0;
}</span></span></strong>