Q:
A:
所有人说的都是谎话,所以3个条件 就是
a != 0 && 0 != c && c != 2 (用 a=0 表示新郎a和x结婚,同理不结婚则表示a!=0)
同时隐含条件就是3个新郎不能互为配偶(也就是说两个新娘不可嫁给一个人)
所以a!=b && a!=c && b!=c
#include<iostream>
using namespace std;
int main() {
//groom
int a, b, c;
//bride 0 1 2
char X = 'X';
for (a = 0; a<3 ; a++) {
for (b = 0; b<3 ; b++) {
for (c = 0; c<3 ; c++) {
//a is not married to X, X is not married to c, c is not married to Z
if(a != 0 && 0 != c && c != 2 && a!=b && a!=c && b!=c){
cout<<"A married "<<(char)(X+a)<<endl;
cout<<"B married "<<(char)(X+b)<<endl;
cout<<"C married "<<(char)(X+c)<<endl;
}
}
}
}
return 0;
}