sql 取表的前10條記錄，任意中間幾行的記錄

取表的前10條記錄
with a as(select *,row_number()over(order by department)rn from _SucceedStaff )

select * from a where rn<=10

取表的任意中間幾行的記錄eg：10-30
with a as(select *,row_number()over(order by department)rn from _SucceedStaff )
select * from a where rn>=10 and rm<=30

附：常用幾種數據庫，取前10條記錄的sql語句寫法
http://blog.csdn.net/lzz313/archive/2006/12/19/1449572.aspx

access：
select top (10) * from table1 where 1=1

db2：
select column from table where 1=1 fetch first 10 rows only

mysql：
select * from table1 where 1=1 limit 10

sql server:
讀取前10條：select top (10) * from table1 where 1=1
讀取後10條：select top (10) * from table1 order by id desc

oracle：
select * from table1 where rownum<=10

取每日日期的前十條記錄

SQL表列如下：

單號 日期
1 2011-09-10
2 2011-09-10

select * from tb a where 單號 in(select top 10 單號 from tb where 日期=a.日期 order by 單號)

select * from (
select *,rank () over(partition by day(日期) order by 日期) rk from tb
) t
where t.rk<=10

select * from(select *,row_number()over(order by name)rn from _SucceedStaff )t
where t.rn<=10（對比上面）