Python 練習4

題目：輸入某年某月某日，判斷這一天是這一年的第幾天？
程序分析：以3月5日爲例，應該先把前兩個月的加起來，然後再加上5天即本年的第幾天，特殊情況，閏年且輸入月份大於2時需考慮多加一天：
首先可以考慮使用一個數組

閏年：1.能被4整除但不能被100整除的年份
2.能被400整除的年份。

答案1

year = int(input('年'))
mouth = int(input('月'))
day = int(input('日'))

mouth_arr = list(range(1, 13))
day_arr = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
result = 0
flag = 0
if (year % 4 == 0 and year % 100 != 0) or (year % 400 == 0):
    flag = 1
if mouth > 2:
    day_arr[1] = 29
for i in mouth_arr:
    if mouth > i:
        result += day_arr[i]
    elif mouth == i:
        result += day
print(result)

python2

#!/usr/bin/python
# -*- coding: UTF-8 -*-
year = int(raw_input('year:\n'))
month = int(raw_input('month:\n'))
day = int(raw_input('day:\n'))
months = (0,31,59,90,120,151,181,212,243,273,304,334)
if 0 < month <= 12:
    sum = months[month - 1]
else:
    print 'data error'
sum += day
leap = 0
if (year % 400 == 0) or ((year % 4 == 0) and (year % 100 != 0)):
    leap = 1
if (leap == 1) and (month > 2):
    sum += 1
print 'it is the %dth day.' % sum