1.Description
Given an integer array, you need to find one continuous subarray that if you only sort this subarray in ascending order, then the whole array will be sorted in ascending order, too.
You need to find the shortest such subarray and output its length.
Example 1:
**Input:** [2, 6, 4, 8, 10, 9, 15] **Output:** 5 **Explanation:** You need to sort [6, 4, 8, 10, 9] in ascending order to make the whole array sorted in ascending order.
Note:
- Then length of the input array is in range [1, 10,000].
- The input array may contain duplicates, so ascending order here means <=.
解读
确定序列中无序子序列的长度
2.Solution
思路:可以通过排序的方式,确定左右边界,返回即可
#Method:通过排序确定左右边界
class Solution(object):
def findUnsortedSubarray(self, nums):
n, sorts,left,right= len(nums), sorted(nums),0,0
if nums == sorts: return 0
#找到左侧边界
for i in range(n):
if nums[i] != sorts[i]:
l = i
break
#找到右侧边界
for i in range(n-1,-1,-1):
#print(i)
if nums[i] != sorts[i]:
r = i
break
return r - l + 1