在java中使用xpath來解析xml文件

DocumentBuilderFactory domFactory = DocumentBuilderFactory
				.newInstance();
		DocumentBuilder builder = domFactory.newDocumentBuilder();

                domFactory.setNamespaceAware(false);//這句話可有可無,但是不知道爲什麼設置成true就無法解析了,可能跟命名空間有關吧..以後再研究
		Document doc = builder.parse("config1.xml");
		XPathFactory factory = XPathFactory.newInstance();
		XPath xpath = factory.newXPath();
		XPathExpression expr = xpath.compile("//name/text()");
		Object result = expr.evaluate(doc, XPathConstants.NODESET);
		NodeList nodes = (NodeList) result;
		for (int i = 0; i < nodes.getLength(); i++) {
			System.out.println(nodes.item(i).getNodeValue());
		}