A+B
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2805 Accepted Submission(s): 1592
現在請計算A+B的結果,並以正常形式輸出。
#include<stdio.h>
#include<string.h>
int main()
{
char a[50],b[50];
while(~scanf("%s %s",a,b))
{
int sum,sum1=0,sum2=0;
//puts(a);
//puts(b);
int l1,l2,i,x,y;
l1=strlen(a);
l2=strlen(b);
for(i=0;i<l1;i++)
if(a[i]!=','&&a[i]!='-')
{
a[i]-='0';
sum1=sum1*10+a[i];
}
//printf("%d",sum1);
//printf("\n");
for(i=0;i<l2;i++)
if(b[i]!=','&&b[i]!='-')
{
b[i]-='0';
sum2=sum2*10+b[i];
}
if(a[0]=='-')
sum1=-sum1;
if(b[0]=='-')
sum2=-sum2;
sum=sum1+sum2;
printf("%d\n",sum);
}
return 0;
}