題目:
Given a binary tree, return the inorder traversal of its nodes' values.
Example:
Input: [1,null,2,3] 1 \ 2 / 3 Output: [1,3,2]
代碼:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void backInorder(TreeNode* root, vector<int>& res) {
if(root == NULL)
return;
backInorder(root->left, res);
res.push_back(root->val);
backInorder(root->right, res);
return;
}
vector<int> inorderTraversal(TreeNode* root) {
vector<int> res;
backInorder(root, res);
return res;
}
};