Leetcode 1476.子矩形查詢（Subrectangle Queries）

Leetcode 1476.子矩形查詢

1 題目描述（Leetcode題目鏈接）

  請你實現一個類 SubrectangleQueries ，它的構造函數的參數是一個 rows x cols 的矩形（這裏用整數矩陣表示），並支持以下兩種操作：

1. updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)

用 newValue 更新以 (row1,col1) 爲左上角且以 (row2,col2) 爲右下角的子矩形。
2. getValue(int row, int col)

返回矩形中座標 (row,col) 的當前值。

輸入：
["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue","getValue"]
[[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]]
輸出：
[null,1,null,5,5,null,10,5]
解釋：
SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]);  
// 初始的 (4x3) 矩形如下：
// 1 2 1
// 4 3 4
// 3 2 1
// 1 1 1
subrectangleQueries.getValue(0, 2); // 返回 1
subrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5);
// 此次更新後矩形變爲：
// 5 5 5
// 5 5 5
// 5 5 5
// 5 5 5 
subrectangleQueries.getValue(0, 2); // 返回 5
subrectangleQueries.getValue(3, 1); // 返回 5
subrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10);
// 此次更新後矩形變爲：
// 5   5   5
// 5   5   5
// 5   5   5
// 10  10  10 
subrectangleQueries.getValue(3, 1); // 返回 10
subrectangleQueries.getValue(0, 2); // 返回 5

提示：

• 最多有 500 次updateSubrectangle 和 getValue 操作。
• 1 <= rows, cols <= 100
• rows == rectangle.length
• cols == rectangle[i].length
• 0 <= row1 <= row2 < rows
• 0 <= col1 <= col2 < cols
• 1 <= newValue, rectangle[i][j] <= 10^9
• 0 <= row < rows
• 0 <= col < cols

2 題解

  暴力解。

class SubrectangleQueries:

    def __init__(self, rectangle: List[List[int]]):
        self.rectangle = rectangle


    def updateSubrectangle(self, row1: int, col1: int, row2: int, col2: int, newValue: int) -> None:
        for i in range(row1, row2 + 1):
            for j in range(col1, col2 + 1):
                self.rectangle[i][j] = newValue


    def getValue(self, row: int, col: int) -> int:
        return self.rectangle[row][col]



# Your SubrectangleQueries object will be instantiated and called as such:
# obj = SubrectangleQueries(rectangle)
# obj.updateSubrectangle(row1,col1,row2,col2,newValue)
# param_2 = obj.getValue(row,col)