例:Test test = new Test();
test.setId("1");
test.setName("zhangsan");
jsonObject.fromobject(test,Test.class).toString;
输出:{"id":"1","name":"zhangsan"}
假如不封装name属性,只封装id属性
Test test = new Test();
test.setId("1");
jsonObject.fromobject(test,Test.class).toString;
输出:{"id":"1","name":""}
如果只输出:{"id":"1"}
这样的json字符,有什么方法可以解决么?
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public static void main(String[] args) { Test t = new Test(); t.id = 10 ; JsonConfig jsonConfig = new JsonConfig(); PropertyFilter filter = new PropertyFilter() { public boolean apply(Object object, String fieldName, Object fieldValue) { return null == fieldValue; } }; jsonConfig.setJsonPropertyFilter(filter); System.out.println(JSONObject.fromObject(t, jsonConfig).toString()); } |