編寫函數，要求輸入年月日時分秒，輸出該時間的下一秒

#include
#include <string>
using namespace std;


void ResetTheTime(int *year,int *month,int *date,int *hour,int *minute,int *second)
{
int dayofMonth[12]={31,28,31,30,31,30,31,31,30,31,30,31};


if (*year <0 || *month <1 || *month >12 || *date <1 ||*date >31

||*hour <0 ||*hour >23 || *minute <0 ||*minute>59 || *second <0 || *second >59)
{
return ;
}




if (*year <0 || *month < 1 || *month >12)
{
if (*year%400==0 || *year%100 !=0 && *year%4 ==0)
dayofMonth[1]=29;
}


*second +=1;
if (*second >=60)
{
*second =0;
*minute +=1;
if (*minute >=60)
{
*minute = 0;
*hour+=1;
if (*hour >= 24)
{
*hour =0;
*date +=1;
if (*date > dayofMonth[*month -1])
{
*date =1;
*month +=1;
if (*month >12)
{
*month =1;
*year +=1;
}
}
}
}

}


cout <<*year << ' '<<*month << " " << *date << ' ' << *hour << ' ' << *minute << ' ' << *second;
return ;
}


int main()
{
int y1=2004;int m1=2; int d1=28;
int h1=23; int mm=59; int sec=59;


ResetTheTime(&y1,&m1,&d1,&h1,&mm,&sec);


return 0;
}