Python 實現簡單的通訊錄

簡單的通訊錄實現，A byte of Python的例子

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#!/bin/python #coding=utf8 import os try:     import cPickle as p except:     import pickle as p   class Person:     def __init__(self,name,mobile='',email='',address=''):         self.name = name         self.mobile = mobile         self.email = email         self.address = address       def modifyInfo(self,mobile,email,address):         self.mobile = mobile         self.email = email         self.address = address   if os.path.exists("./contact.data")==False:     dirlist = {}     p.dump(dirlist,open("./contact.data",'w'),1)   print "請輸入要進行的操作（添加:a,刪除：d，修改:m,查找:f,退出:q）" dict = p.load(open("./contact.data",'r')) flag = True while flag:     choice = raw_input("請選擇你的操作:a,d,m,f,q")     if choice == 'a':         n1 = raw_input("姓名:")         m1 = raw_input("電話")         e1 = raw_input("郵箱")         a1 = raw_input("地址")         per = Person(n1,m1,e1,a1)         dict[n1]=per         print '添加%s成功\n'%n1     elif choice == 'd':         n2 = raw_input("姓名")         del dict[n2]         print '刪除%s成功\n'%n2     elif choice == 'm':         n3 = raw_input("姓名")         m3 = raw_input("電話")         e3 = raw_input("郵箱")         a3 = raw_input("地址")         per3 = dict[n3]         per3.modifyInfo(m3,e3,a3)         dict[n3] = per3         print '修改%s成功\n'%n3     elif choice == 'f':             n4 = raw_input("姓名")         try:                per4 = dict[n4]             print '%s 的信息如下'%n4             print '手機:%s,郵箱:%s,地址:%s'%(per4.mobile,per4.email,per4.address)         except Exception,e:             print e #打印異常信息<br>　　　　　　　　　　　　　　<code class="functions">print</code><span> </span><code class="plain">traceback.format_exc()</code>             print '不存在這個人%s'%n4     elif choice == 'q':         p.dump(dict,open("./contact.data",'w'),1)         flag = False     else:         print '請輸入正確的選項'         continue