我如何解决JavaScript的parseInt八进制行为？ - How do I work around JavaScript's parseInt octal behavior?

问题：

Try executing the following in JavaScript: 尝试在JavaScript中执行以下操作：

parseInt('01'); //equals 1
parseInt('02'); //equals 2
parseInt('03'); //equals 3
parseInt('04'); //equals 4
parseInt('05'); //equals 5
parseInt('06'); //equals 6
parseInt('07'); //equals 7
parseInt('08'); //equals 0 !!
parseInt('09'); //equals 0 !!

I just learned the hard way that JavaScript thinks the leading zero indicates an octal integer , and since there is no "8" or "9" in base-8, the function returns zero. 我刚刚学会了JavaScript认为前导零表示八进制整数的困难方式，并且由于base-8中没有"8"或"9" ，因此该函数返回零。 Like it or not, this is by design . 无论喜欢与否， 这都是设计的 。

What are the workarounds? 解决方法有哪些？

Note: For sake of completeness, I'm about to post a solution, but it's a solution that I hate, so please post other/better answers. 注意：为了完整起见，我即将发布解决方案，但这是我讨厌的解决方案，所以请发布其他/更好的答案。

---

Update: 更新：

The 5th Edition of the JavaScript standard ( ECMA-262 ) introduces a breaking change that eliminates this behavior. JavaScript标准的第5版（ ECMA-262 ）引入了一个突破性的变化，消除了这种行为。 Mozilla has a good write-up . Mozilla 写得很好。

---

解决方案：

参考一： https://stackoom.com/question/3ZDB
参考二： How do I work around JavaScript's parseInt octal behavior?