我如何解决JavaScript的parseInt八进制行为? - How do I work around JavaScript's parseInt octal behavior?

问题:

Try executing the following in JavaScript: 尝试在JavaScript中执行以下操作:

parseInt('01'); //equals 1
parseInt('02'); //equals 2
parseInt('03'); //equals 3
parseInt('04'); //equals 4
parseInt('05'); //equals 5
parseInt('06'); //equals 6
parseInt('07'); //equals 7
parseInt('08'); //equals 0 !!
parseInt('09'); //equals 0 !!

I just learned the hard way that JavaScript thinks the leading zero indicates an octal integer , and since there is no "8" or "9" in base-8, the function returns zero. 我刚刚学会了JavaScript认为前导零表示八进制整数的困难方式,并且由于base-8中没有"8""9" ,因此该函数返回零。 Like it or not, this is by design . 无论喜欢与否, 这都是设计的

What are the workarounds? 解决方法有哪些?

Note: For sake of completeness, I'm about to post a solution, but it's a solution that I hate, so please post other/better answers. 注意:为了完整起见,我即将发布解决方案,但这是我讨厌的解决方案,所以请发布其他/更好的答案。


Update: 更新:

The 5th Edition of the JavaScript standard ( ECMA-262 ) introduces a breaking change that eliminates this behavior. JavaScript标准的第5版( ECMA-262 )引入了一个突破性的变化,消除了这种行为。 Mozilla has a good write-up . Mozilla 写得很好。


解决方案:

参考一: https://stackoom.com/question/3ZDB
参考二: How do I work around JavaScript's parseInt octal behavior?
發表評論
所有評論
還沒有人評論,想成為第一個評論的人麼? 請在上方評論欄輸入並且點擊發布.
相關文章