How to query all the GraphQL type fields without writing a long query?

問題：

Assume you have a GraphQL type and it includes many fields.假設您有一個 GraphQL 類型並且它包含許多字段。 How to query all the fields without writing down a long query that includes the names of all the fields?如何在不寫下包含所有字段名稱的長查詢的情況下查詢所有字段？

For example, If I have these fields :例如，如果我有這些字段：

 public function fields()
    {
        return [
            'id' => [
                'type' => Type::nonNull(Type::string()),
                'description' => 'The id of the user'
            ],
            'username' => [
                'type' => Type::string(),
                'description' => 'The email of user'
            ], 
             'count' => [
                'type' => Type::int(),
                'description' => 'login count for the user'
            ]

        ];
    }

To query all the fields usually the query is something like this:要查詢所有字段，通常查詢是這樣的：

FetchUsers{users(id:"2"){id,username,count}}

But I want a way to have the same results without writing all the fields, something like this:但我想要一種無需編寫所有字段即可獲得相同結果的方法，如下所示：

FetchUsers{users(id:"2"){*}}
//or
FetchUsers{users(id:"2")}

Is there a way to do this in GraphQL ??有沒有辦法在 GraphQL 中做到這一點？

I'm using Folkloreatelier/laravel-graphql library.我正在使用Folkloreatelier/laravel-graphql庫。

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解決方案：

參考一： https://en.stackoom.com/question/2JUyc
參考二： https://stackoom.com/question/2JUyc