如何从扩展的 PHP 类中的静态调用中获取类名？ - How can I get the classname from a static call in an extended PHP class?

问题：

I have two classes: Action and MyAction .我有两个类： Action和MyAction 。 The latter is declared as:后者声明为：

class MyAction extends Action {/* some methods here */}

All I need is method in the Action class (only in it, because there will be a lot of inherited classes, and I don't want to implement this method in all of them), which will return classname from a static call.我所需要的只是Action类中的方法（只在其中，因为会有很多继承的类，我不想在所有这些类中都实现这个方法），它将从静态调用中返回类名。 Here is what I'm talking about:这就是我要说的：

Class Action {
 function n(){/* something */}
}

And when I call it:当我调用它时：

MyAction::n(); // it should return "MyAction"

But each declaration in the parent class has access only to the parent class __CLASS__ variable, which has the value “Action”.但是父类中的每个声明只能访问父类__CLASS__变量，该变量的值为“Action”。

Is there any possible way to do this?有没有可能的方法来做到这一点？

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解决方案：

参考： https://stackoom.com/en/question/27of