題目
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9,
Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].
思路
直觀思路是使用兩個for循環遍歷nums,然後if判斷。
class Solution(object):
def two_sum1(self, nums, target):
for i in range(0, len(nums)):
for j in range(i+1, len(nums)):
if((nums[i]+nums[j])==target):
a = i
b = j
return[a, b]
Submit後AC,但是這種暴力搜索的時間複雜度較高。另一種更快速的方法是哈希法。
class Solution:
def twoSum(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
d = {}
for i, j in enumerate(nums):
if target - j in d:
return(d[target-j], i)
else:
d[j] = i