使用那麼多的接口了,開始從正則開始記錄吧,還是得養成記錄的習慣,將已經寫好的代碼放出來,這纔是你自己的,同時也是大家的。
#include <regex.h>
int main()
{
int status ,i;
int cflags = REG_EXTENDED;
regmatch_t pmatch[10];
const size_t nmatch = 10;
regex_t reg;
char match[100];
//char data[10][100] = {0};
char data[nmatch][100];
memset(data,0x0,sizeof(data));
//printf("sizeof data %d\n", sizeof(data));
const char * pattern = "^[^:]+: *([a-zA-Z]) *, *([\-]*[0-9]+) *, *Speed *: *([0-9]+) *, *Acc *: *([0-9]+)$";
//const char * pattern = "^[^:]+: *([a-zA-Z]) *, *([\-|0-9][0-9]*) *, *Speed *: *([0-9]+) *, *Acc *: *([0-9]+)$";
char * buf = "SingleAxis : x, -100 , Speed: 30,Acc : 30";
regcomp(®,pattern,cflags);//編譯正則模式
status = regexec(®,buf,nmatch,pmatch,0);//執行正則表達式和緩存的比較
if(status == REG_NOMATCH)
printf("No match\n");
else if (0 == status)
{
for(int i=0; i < 10 && pmatch[i].rm_so != -1; i++) {
int len = pmatch[i].rm_eo - pmatch[i].rm_so;
printf("i %d => len:%d\n",i,len);
if(len) {
memset(match,'\0',sizeof(match));
memcpy(match, buf + pmatch[i].rm_so,len);
// get axis distance speed acc from i == 1
printf("match %d:%s\n",i,match);
if(i >= 1) {
printf("ready to copy to data[%d] addr %p\n",i-1,data[i-1]);
printf("len now is %d\n", len);
memcpy(data[i-1],match,len);
printf("length:%d\n",strlen(data[i-1]));
printf("data[%d]:%s\n",i,data[i-1]);
}
}
}
}
}
簡要的使用流程按照如上形式即可,這裏對正則表達式做一些說明。
注意:
regexec
需要判斷結果pmatch
數組中存放者匹配的結果- 如果需要類似
python
中的group
的功能,需要在匹配表達式中加上()
regmatch_t
結構體中的rm_eo
,rm_so
分別表明了匹配的開始和結束,兩者相減 表明了匹配的長度
運行結果:
i 0 => len:43
match 0:SingleAxis : x, -100 , Speed: 30,Acc : 30
i 1 => len:1
match 1:x
ready to copy to data[0] addr 0x7ffef92cc340
len now is 1
length:1
data[1]:x
i 2 => len:4
match 2:-100
ready to copy to data[1] addr 0x7ffef92cc3a4
len now is 4
length:4
data[2]:-100
i 3 => len:2
match 3:30
ready to copy to data[2] addr 0x7ffef92cc408
len now is 2
length:2
data[3]:30
i 4 => len:2
match 4:30
ready to copy to data[3] addr 0x7ffef92cc46c
len now is 2
length:2
data[4]:30