[LeetCode]Remove Element

題目：

Remove Element

 

Given an array and a value, remove all instances of that value in place and return the new length.

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

來源：http://oj.leetcode.com/problems/remove-element/

思路：

題意：給定一個數組和一個值，就地刪除該值的所有實例，並返回新的長度。
元素的順序是可以改變的。除了新的長度外，留下啥都不要緊。

C++ AC代碼：

class Solution {
public:
    int removeElement(int A[], int n, int elem) {
        int new_length = 0;
		for (int i = 0; i < n; i++ ){
		    if (A[i] != elem ){
			    A[new_length] = A[i];
				new_length++;
				}
		}
		return new_length;
    }
};

運行時間 16ms