題目:Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
For example,
Given input array nums = [1,1,2],
Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn’t matter what you leave beyond the new length.
思路:
- 用len保存當前沒有重複的vector長度,當下一個元素月當前的nums[len]不同時,就把此元素賦給nums[len+1]
C++代碼如下:
int removeDuplicates(vector<int>& nums) {
if (nums.size() <= 1)
return nums.size();
int len = 0;
for (int i = 1; i < nums.size(); i++)
{
if (nums[len] != nums[i])
{
nums[++len] = nums[i];
}
}
return len + 1;
}