#include <algorithm>
#include <iostream>
#include <stdio.h>
#include <queue>
#include <string.h>
using namespace std;
struct node
{
int x, y, z;
int step;
};
int x,y,z,sx,sy,sz,ex,ey,ez;
char map[40][40][40];
int book[40][40][40];
int dx[] = {1,-1,0,0,0,0};
int dy[] = {0,0,1,-1,0,0};
int dz[] = {0,0,0,0,1,-1};
int check(node a)
{
if(a.x>=0&&a.x<x&&a.y>=0&&a.y<y&&a.z>=0&&a.z<z&&!book[a.x][a.y][a.z]&&map[a.x][a.y][a.z]!='#')
return 1;
else
return 0;
}
int BFS()
{
queue<node>Q;
node a, next,q;
a.x = sx;
a.y = sy;
a.z = sz;
book[sx][sy][sz] = 1;
a.step = 0;
Q.push(a);
while(!Q.empty()){
q = Q.front();
Q.pop();
if(q.x==ex&&q.y==ey&&q.z==ez){
return q.step;
}
for(int i = 0;i < 6;i++){
next.x = q.x+dx[i];
next.y = q.y+dy[i];
next.z = q.z+dz[i];
if(check(next)){
book[next.x][next.y][next.z] = 1;
next.step = q.step+1;
Q.push(next);
}
}
}
return -1;
}
int main()
{
while(~scanf("%d %d %d", &x, &y, &z)){
if(x==0&&y==0&&z==0) break;
for(int i = 0;i < x;i++){
for(int j = 0;j < y;j++){
scanf("%s", map[i][j]);
for(int k = 0;k < z;k++){
if(map[i][j][k] == 'S'){
sx = i;
sy = j;
sz = k;
}else if(map[i][j][k] == 'E'){
ex = i;
ey = j;
ez = k;
}
}
}
}
memset(book,0,sizeof(book));
int t = BFS();
if(t == -1){
printf("Trapped!\n");
}else {
printf("Escaped in %d minute(s).\n", t);
}
}
return 0;
}
POJ 2251 Dungeon Master 三維BFS
注意x,y,z的方向,簡單的BFS
發表評論
所有評論
還沒有人評論,想成為第一個評論的人麼? 請在上方評論欄輸入並且點擊發布.