You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
鏈表操作,相當於高精度
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *addTwoNumbers(ListNode *l1, ListNode *l2) {
ListNode *head,*p,*s;
head=(ListNode*)malloc(sizeof(ListNode));
p=head;
int a,a1,a2,a3;
int tmp=0;
while(1){
if(l1!=NULL) a1=l1->val;
else a1=0;
if(l2!=NULL) a2=l2->val;
else a2=0;
a3=a1+a2+tmp;
a=a3%10;
tmp=a3/10;
s=(ListNode*)malloc(sizeof(ListNode));
s->val=a;
p->next=s;
p=s;
if(l1!=NULL) l1=l1->next;
if(l2!=NULL) l2=l2->next;
if(l1==NULL && l2==NULL && tmp==0)
break;
}
head=head->next;
p->next=NULL;
return (head);
}
};