枚舉最小精度爲單位的角度
#include<cstdio>
#include<algorithm>#include<cstring>
#include<cmath>
using namespace std;
double v[210];
#define pi 4*atan(1)
int main()
{
int n;
while(scanf("%d",&n)!=EOF&&n)
{
double h,l1,r1,l2,r2;
scanf("%lf%lf%lf%lf%lf",&h,&l1,&r1,&l2,&r2);
for(int i=1;i<=n;i++)
{
scanf("%lf",&v[i]);
}
int num=0;
int res=0;
double i;
for(i=-pi/2.0;i<=pi/2.0;i+=pi/(2.0*10000))
{
num=0;
for(int j=1;j<=n;j++)
{
double vx=v[j]*cos(i);
double vy=v[j]*sin(i);
double vy2=sqrt(vy*vy+2*9.8*h);
double t=(vy2-vy)/9.8;
double x=vx*t;
if(x>=l2&&x<=r2){
num=0;
break;
}
if(x>=l1&&x<=r1){
num++;
}
}
res=max(res,num);
}
printf("%d\n",res);
}
}