UVa1225 Digit Counting 數數字

代碼：

 #include<stdio.h>  
    
int c[10000][10];  
    
int main()  
{  
    int i, k, t, n;  
    for (i = 1; i < 10000; ++i)  
    {  
        for (k = i; k; k /= 10) ++c[i][k % 10];  
        for (; k < 10; ++k) c[i][k] += c[i - 1][k];  
    }  
    scanf("%d", &t);  
    while (t--)  
    {  
        scanf("%d", &n);  
        for (i = 0; i < 9; ++i)  
            printf("%d ", c[n][i]);  
        printf("%d\n", c[n][9]);  
    }  
    return 0;  
}