題目鏈接 771. Jewels and Stones |
You’re given strings J
representing the types of stones that are jewels, and S
representing the stones you have. Each character in S
is a type of stone you have. You want to know how many of the stones you have are also jewels.
The letters in J
are guaranteed distinct, and all characters in J
and S
are letters. Letters are case sensitive, so "a"
is considered a different type of stone from "A"
.
Example 1:
Input: J = "aA", S = "aAAbbbb"
Output: 3
Example 2:
Input: J = "z", S = "ZZ"
Output: 0
Note:
S
andJ
will consist of letters and have length at most 50.- The characters in
J
are distinct.
題意
字符串 J
中每個字符爲寶石,字符串 S
中的每個字符爲自己擁有的石頭,想知道自己擁有多少寶石。
區分大小寫
思路1
- 使用一個哈希表記錄所有的寶石
- 遍歷
S
中的所有石頭,使用ans
記錄寶石的數量
代碼1
class Solution {
public:
int numJewelsInStones(string J, string S) {
bool ch[256] = {true};
for(const auto &it : J)
ch[it] = true;
int ans = 0;
for(const auto &it : S)
if(ch[it])
ans++;
return ans;
}
};