小算法--任意大於3的整數轉化成兩個質數和的總對數

#include <iostream>
#include <cmath>
#define MAX 1000
using namespace std;

int main(int argc, char *argv[])
{
	int X;
	cout << "請輸入X的值：";
	cin >> X;
	if (X > MAX || X < 3)
	{
		cout << "輸入的X不合法！" << endl;
		system("pause");
		return 0;
	}
	int addCount = 0;
	int count = 1;
	int init[MAX] = { 0, 1 };
	int k = 0;
	for (int i = 3; i <= MAX; i++)
	{
		bool isHehe = true;
		for (int j = 2; j <= sqrt(i); j++)
		{
			if (i%j == 0)
			{
				isHehe = false;
				break;
			}
		}
		if (isHehe)
		{
			init[i-1] = 1;
			count++;
		}
	}
	int *hehe = new int[count];
	for (int i = 0; i < MAX; i++)
	{
		if (init[i] == 1)
		{
			hehe[k++] = i + 1;
		}
	}
	for (int i = 0; 2*hehe[i]<=X; i++)
	{
		for (int j = count-1; j >= 0; j--)
		{
			if (hehe[i] + hehe[j] == X)
			{
				addCount++;
				cout << hehe[i] << " " << hehe[j] << endl;
				break;
			}
			if (hehe[i] + hehe[j] < X)
			{
				break;
			}
		}
	}
	cout << "輸入的X值可以轉化爲 " << addCount << " 對質數之和！" << endl;
	delete[] hehe;
	system("pause");
	return 0;
}