全阶BOM算法

因为工作的因素，涉及到Bom与工时比较多，就想着如何利用现有的系统体现出全阶BOM。以下图为例：

在系统系统中的存储方式如下：

P：父项；C：子件；SortSeq：行号，QTY：用量

if OBJECT_ID('SBom') is not null
begin
	drop table SBom
end 
select 1 as L, P+'-'+RTRIM(CAST(SORTSEQ AS CHAR)) AS LEV,P,SORTSEQ,C,QTY,qty as Sqty  into SBom from bom where P='a'

DECLARE @ID AS INT 
SET @ID=0
WHILE @ID<1
	BEGIN
		INSERT INTO SBOM(L,Lev,p,sortseq,c,qty,sqty)
		select t1.L+1 as L,t1.lev+'-'+rtrim(cast(t2.sortseq as char)) as Lev,
		t1.p,t2.sortseq,t2.c,t2.qty,t1.Sqty*t2.qty as Sqty from 
		(
		select L,LEV,P,SORTSEQ,C,QTY,Sqty from SBom where L in(select MAX(l) from SBom)
		)t1
		INNER join bom t2 on t1.c=t2.p
		SELECT @ID=CASE WHEN ISNULL(COUNT(1),0)>0 THEN 0 ELSE 1 END  FROM SBOM T1 
		INNER JOIN BOM T2 ON T1.C=T2.P
		WHERE T1.l IN(SELECT MAX(L) FROM SBOM)
	END

这里Sbom是最终存储的全阶Bom，最终的效果如下：

这样可以较为轻易地完成全阶BOM

对于工时的运算，也是同理的。希望给在制造一线的兄弟们，抛砖引玉吧！