[leetcode] Max Points on a Line

題目：

Max Points on a Line

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Given n points on a 2D plane, find the maximum number of points that lie on the same straight line.

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代碼如下，已經註釋

class Solution {
public:
	int maxPoints(vector<Point> &points)
	{
		if (points.size() == 0) return 0;
		int result = 0; //存儲結果
		for (int index = 0; index < points.size(); index++)
		{
			unordered_map<float, int> mp;//使用map也可以，unorder_map是C++ 11加進去的
			int same = 1;//相同的點的數目

			for (int in = 0; in < points.size(); in++)//兩次循環便利
			{
				if (index == in) continue;//同一個點，跳過
				if (points[index].x == points[in].x && points[index].y == points[in].y)
				{//假如爲座標相同的點（points中有重複數據）
					same++; continue;
				}
				//當斜率正無窮時，使用INT_MAX，FLT_MAX都是可以的
				if (points[index].x == points[in].x) mp[INT_MAX]++;
				else
				{
					float k = ((float)(points[index].y - points[in].y)) / (points[index].x - points[in].x);
					mp[k]++;
				}
			}
			for (std::unordered_map<float, int>::iterator it = mp.begin(); it != mp.end(); it++)
			{//查找最大值
				if (it->second + same > result) result = it->second + same;
			}
			if (same > result) result = same;
		}

		return result;
	}
};

88毫秒通過