題目描述:
Bobo has two sets of integers A = {a1,a2,…,an}and B = {b1,b2,…,bn}
He says that x∈span(A) (or span(B)) if and only if there exists a subset of A (or B) whose exclusive-or sum equals to x.
Bobo would like to know the number of x where x∈span(A) and x∈span(B) hold simultaneously.
輸入描述:
The input contains zero or more test cases and is terminated by end-of-file. For each test case:
The first line contains an integer n.
The second line contains n integers a1,a2,…an
The third line contains n integers b1,b2,…,bn
*1≤n≤50
- 0 ≤ ai, bi ≤ 2^60
- The number of test cases does not exceed 5000.
輸出描述:
For each case, output an integer which denotes the result.
題意:
給出A,B兩個數組,定義x在Span(A)集合裏爲:A的一個子集的異或和爲x(可以是空集),求有多少個x即在Span(A)也在Span(B)中。
題解:
構造A,B線性基,對A中的每個基在B中訪問並存儲,更新答案
code:
#include<bits/stdc++.h>
#define ll long long
using namespace std;
ll a[61],b[61];
bool insert(ll x,ll *t)
{
for(int i=60;i>=0;i--)
{
if(!((1ll<<i)&x))continue;
if(!t[i])
{
t[i]=x;
return false;
}
else x^=t[i];
if(!x)return true;
}
return true;
}
int main()
{
int n;
while(~scanf("%d",&n))
{
ll p;
memset(a,0,sizeof a);
memset(b,0,sizeof b);
for(int i=1;i<=n;i++)
{
scanf("%lld",&p);
insert(p,a);
}
for(int i=1;i<=n;i++)
{
scanf("%lld",&p);
insert(p,b);
}
ll ans=1;
for(int i=60;i>=0;i--)
{
if(!b[i])continue;
if(insert(b[i],a))ans<<=1;
}
printf("%lld\n",ans);
}
return 0;
}