MZL's xor
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1264 Accepted Submission(s): 784
The xor of an array B is defined as B1 xor B2...xor Bn
Each test case contains four integers:n,m,z,l
A1=0,Ai=(Ai−1∗m+z) mod l
1≤m,z,l≤5∗105,n=5∗105
code
#include <iostream>
#include<cstdio>
using namespace std;
#define MAXN 500010
#define LL long long
LL a[MAXN];
int main()
{
int t,m,n,z,l;
scanf("%d",&t);
while(t--)
{
scanf("%d%d%d%d",&n,&m,&z,&l);
a[1]=0;
for(int i=2;i<=n;i++)
{
a[i]=(a[i-1]*m+z)%l;
}
long long ans=0;
for(int i=1;i<=n;i++)
{
ans=ans^(2*a[i]);
}
printf("%lld\n",ans);
}
return 0;
}