1132 Cut Integer (20分)
Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A and B, as 167334 / (167 × 334) = 3. Given an integer Z, you are supposed to test if it is such an integer.
Input Specification:
Each input file contains one test case. For each case, the first line gives a positive integer N (≤ 20). Then N lines follow, each gives an integer Z (10 ≤ Z <231). It is guaranteed that the number of digits of Z is an even number.
Output Specification:
For each case, print a single line Yes
if it is such a number, or No
if not.
Sample Input:
3
167334
2333
12345678
Sample Output:
Yes
No
No
很简单一道题
但是我错在了细节
之前所有错的,全是因为if括号内n的位置,先进行d%n==0 n有可能为0 报浮点错误
如果把n放在&&前,就不会了,
跟&&的特点有关。
A&&B 如果A是false,他就不会在乎B是啥了
细节决定成败!
#include<iostream>
using namespace std;
int count(int d){
int c=0;
while(d){
c++;
d/=10;
}
return c;
}
int main(){
int n,t,d;
int i,j,k,m;
cin>>m;
while(m--){
cin>>d;
k=count(d);
j=1;
k/=2;
for(i=0;i<k;i++){
j*=10;
}
n=(d/j)*(d%j);
if(n&&d%n==0)
cout<<"Yes"<<endl;
else
cout<<"No"<<endl;
}
}