Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements equal, where a move is incrementing n - 1 elements by 1.
Example:
**Input:** [1,2,3] **Output:** 3 **Explanation:** Only three moves are needed (remember each move increments two elements): [1,2,3] => [2,3,3] => [3,4,3] => [4,4,4]
大意是講 n個數,每次要增加n-1個(那不就是減小一個數嗎)問最多增加多少次(那不就是減少多少次嗎)?
反過來想就簡單了。即減少多少次能到全相等。
class Solution(object):
def minMoves(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
m=min(nums)
ans=0
for i in nums:
ans+=i-m
return ans